Electric Supercharger???

Just had a look at there web site under customer feed back.

This is what one person said
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"Why would anyone spend the time and thousands of dollars on a traditional supercharger when your product does the same thing?"

Chris Ingler
Walnut Creek, CA
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SURE IT DOES!

Big differance between a said 20 to 30 HP gain compared to a gaureteed 100 HP gain....I know what I would sooner have.

Regards Richard

your summing up "IMHO waste of money, time and energy" is right...when it comes to those things...its just that the preceding info is based upon what? BS i reckon......."1000a @13.5 volt is the requirement to give a decent boost"....did you make this up
explain yourself...it wouldnt take a 1000a to drive a positive displacement rotor to provide a positive boost pressure of say 7-10lb intake pressure......

my 998 mini deluxe would'nt have been able to drive a 1000a genny...but with blower was able to take on cooper s's of the day with a 7lb boost...at 10 lb+ it could smoke up the wheels in 4th....

oh and second gear didnt last long but.......

and lets tell all the story by not just quoting kW....tell us all about the whopping increase in torque one gets.........

your summing up "IMHO waste of money, time and energy" is right...when it comes to those things...its just that the preceding info is based upon what? BS i reckon......."1000a @13.5 volt is the requirement to give a decent boost"....did you make this up
explain yourself...it wouldnt take a 1000a to drive a positive displacement rotor to provide a positive boost pressure of say 7-10lb intake pressure......

my 998 mini deluxe would'nt have been able to drive a 1000a genny...but with blower was able to take on cooper s's of the day with a 7lb boost...at 10 lb+ it could smoke up the wheels in 4th....

oh and second gear didnt last long but.......

and lets tell all the story by not just quoting kW....tell us all about the whopping increase in torque one gets.........

I have read this "typical number of 15 KW" somewhere a while back and now do not remember where. My gut feeling is that about to be right, I can easy accept difference in two times, but definitely not 10. Initial curiosity arouse from fact that they use serious belt set-up to drive compressor. If I would have time I will try to support this numbers by physics at evening. And 1000A came from dividing 15000 per 13.5 (actually it is 1,111.1(1) ).
Cheers.

"Definitely BS. Nothing wrong about using electricity to drive supercharger, just number does not stack properly. It takes a lot of power to compress air, typical numbers around 15 KW at medium boost for smaller engines. 15 KW (about 20 HP, 4 times bigger then good winch!!!) will require more then 1000A at 13.5V. And typical alternator give 80A (and indeed some of then required to run car, use light etc). If we assume realistic numbers (say 10A, thus 0.135 KW @ 100% efficiency) we finish with ridiculously small boost. IMHO waste of money, time and energy.
"

Mate ,,,where did these figures come from,?

Big difference trying to turn 2 screws in a large blower with all that centrifigel mass.(15kw loss ok).....compared to a little shaded pole motor spinning plastic blade(find out how many watts your aircon motor is) how many litres a second it can move ! what static pressure it will create! ,,,,,maybe a gain wouldnt be to far out of reach,

G'day All!
Using this reference http://www.efunda.com/forum/show_message.cfm?start=1&thread=17208&id=17213 and following assumption:
1. Specific heat ratio is 1.4
2. Molecular weight 29
3. 18 degree of Celsius
4. 14.7 PSI ambient pressure
5. 3000 RPM for 4.2L engine
I calculated that it would require around 6KW of power to make boost of 10 PSI. This is theoretical figure for ideal gas compressed by ideal compressor without any heat exchange. Any heat exchange or real-life compressor makes this figure only worst. 6KW of electrical power at 13.5 Volts translates into 6000/13.5=444.4(4) Amps (i.e. like very powerful winch). From another hand ideal 10 Amps electrical motor produced 0.135KW power using ideal compressor and compressing ideal gas will give me boost of 0.2 PSI for my engine. Would I bother? No freaking way!
Cheers.

In electrical Terms

6KW = 6000watts
6000watts / 12volt DC = 500amps


1kw = 1.34 hp

I still think that in theory is should work,,,i dont think it would be plug and play like they suggest,

One would have to work out complete volume with manifold and each cylinder to get any benifit,,,,As previously stated, ON IDLE

Hi cwalkin!
It is 13.5, not 12V, but it does not make any difference (actually it makes it even worse). I personally do not need any extra volume of air at idle, but do need it at high load. 4.2L engine displace 4.2L for two rotation (4 stock), and thus displace 2.1L per revolution so it became 6300L per minute @ 3000RPM or 105L per second. This volume need to be compressed *EACH AND EVERY SECOND* almost twice to achieve 10PSI boost. Do you believe that pocket blower can do it? As I said it first replay – total waste of money, energy and efforts.
Cheers.

not sure that i agree
isnt it only a 1/4 of the engine capacity ...the inlet valve is only open during the fuel intake stage

also we only need to keep the manifold above atmospehric (10psi?) so that we push the fuel air mixture into the cylinder rather than let the down stroke suck it in....we are not neccessarily pressurising the cylinder to 10 psi...just the manifold

a lot of unkowns in here i reckon, making it hard to work out just how much power is required to drive the "charger"...but no doubt someone on here can work it out...i'm not smart enough

Hi no 1!
Stroke down for intake, stroke up to compress, stroke down to make work and stroke up to exhaust. Total 4 strokes per two revolutions. Thus for two revolutions each cylinder suck in 4.2L/6=0.7L air (in diesel case) or fuel mixture (if petrol). Yes, you right that in case of normally aspirated engine it would be a bit less then 0.7 (actually it would be exact 0.7, but a bit less pressure). 0.7L per 2 revolutions means 0.7*3000/2=1050L for each cylinder foe a minute at 3000RPM. Multiply per 6 cylinders give as 1050*6=6300L. And again you right that inside cylinder it would be a bit less then 10PSI boost (in case precisely 10 PSI maintained in manifold), but this discrepancy will be absolutely invisible in traction (mechanical as well as aerodynamic) loss and furthermore would be in some kind of proportion to boost. I.e. “garden blower” will suffer from the same problem. Again I simply state that it require *A LOT* of power to compress air in rate of 105L per second for 10 additional PSI. Try those formulas by yourself.
Cheers.

me try the formulae...not likley....i'll need a computer to do that thanks

ok then,,,,lets not get to involved as im no Automotive Electrical Engineer,

But! from what im trying to say IS,
From what i believe , and i dont know if i have lost track of what we actually set out to reply to , Is that ,
A mechanical blower(Twin screw supercharger) will consume alot more power ,AS STATED 15KW
A little centrifigul blower(like capa) will consume less than a twin screw eaton blower,'

But having a, e.g 50mm diameter plastic supercharger ,that could achieve large RPM,
achieving desired static pressure i.e 10psi , Would be more economicly (if acheivable) than robbing as you stated 15KW from the motor,and

Am i wrong?

But if it did consume 444 amps/ph as stated, then you would need to have a battery/electrical system that was capable of supply that sort of current,
And weight may over throw advantage.

I'm sure the power that would need to be consumed from a plastic blower to get reasonable power figures would be ALOT less thank you think..

I MAY BE WRONG

cheers

Can you use small SLA battery to drive winch? If it idle probably it makes a rotation or two, but it is about it. What is wrong? It supplies the same 12V as your car battery does it? Same here. It *WILL* spin, just effect will be negligible. It is require about 6KW theoretical power to supply 10PSI boost, and nothing can be done about it, otherwise we would use “perpetum mobile” 100 year ago. And practical device will require only more power. Small plastic propeller will not generate even static 10PSI – ABSOLUTELY NO WAY! Otherwise why I would not use high volume pump (what I using to pump my airmattresses) to pump my tyres?
Cheers.