Rear Axle Load Caused by Ball Weight

Submitted: Thursday, Apr 21, 2016 at 18:10
ThreadID: 132193 Views:5583 Replies:6 FollowUps:13
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This has been a topic of discussion recently in our club. I decided to have a go at working it out. I think I have it right. Many of you will have already figured it for yourselves, but here's my method. It's all about moments around the rear axle. Diagram below. Corrections welcome.

You need to know
a) vehicle wheelbase, call it W
b) overhang from rear axle to hitch, call it O
c) ball weight, call it B

First you need to know the downward moment at the rear, = O x B. Call that D

There will be an equal upward moment (loss of weight) at the front axle, which equals the O x B divided by the wheelbase, = O x B / W. Call that U

The lost weight at the front axle has to go somewhere - it goes to the rear axle. So the extra weight on the rear axle is ballweight, B, plus the lost weight at the front, = B plus U.

Example from my BT50 dual cab (measurements approximate):

Wheelbase, W is 3.3 metre
Overhang, O is 1.5 metre
Ballweight, B is 160 kg

Downward moment at rear, D, = 160 x 1.5, = 240.
Loss of weight at front, U, is D/W, = 240/3.3, = 72

Weight on rear axle attributable to 160kg ballweight is B plus U, = 160 plus 72, = 232kg.



It might be interesting to work out your own figures.

Cheers




FrankP

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